How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH
When one mole of Na_2O reacts with water, it yields two moles of NaOH, or 80 g of NaOH, with a mass of 62 g.
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To find out how many grams of Na2O are required to produce 1.60 x 10^2 grams of NaOH, you need to use stoichiometry. Since the balanced equation shows that 1 mole of Na2O produces 2 moles of NaOH, you can use the molar mass of Na2O to find the amount needed. The molar mass of Na2O is 61.98 g/mol. So, you first convert the grams of NaOH to moles, then use the stoichiometric ratio to find the moles of Na2O needed, and finally convert that to grams.
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Convert grams of NaOH to moles: (1.60 \times 10^2 \text{ g NaOH} \times \frac{1 \text{ mol NaOH}}{40.00 \text{ g NaOH}} = 4.00 \text{ mol NaOH})
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Use the stoichiometric ratio to find moles of Na2O: (4.00 \text{ mol NaOH} \times \frac{1 \text{ mol Na2O}}{2 \text{ mol NaOH}} = 2.00 \text{ mol Na2O})
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Convert moles of Na2O to grams: (2.00 \text{ mol Na2O} \times \frac{61.98 \text{ g Na2O}}{1 \text{ mol Na2O}} = 123.96 \text{ g Na2O})
Therefore, 123.96 grams of Na2O are required to produce 1.60 x 10^2 grams of NaOH.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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