How many grams of #KI# must be dissolved in 250.0 mL of solution to form a 0.075 M solution?

Answer 1

Approx. #3*g#

#"Concentration "="Moles"/"Volume"#

Here we are given the volume and the concentration and can thus find the molar quantity, and from this we find the mass of #KI#.

#"Moles "=0.075*mol*cancel(L^-1)xx250.0xx10^-3cancelL# #=# #1.875xx10^-3*mol#.

#"Mass"# #=# #"moles"xx"molar mass"#

#=# #1.875xx10^-3*cancel(mol)xx166.0*g*cancel(mol^-1)# #~=3*g#

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Answer 2

Naomi Aronson

To prepare a 0.075 M solution of potassium iodide (KI) in 250.0 mL of solution, you would need to dissolve 11.8 grams of KI.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.