# How many grams are in 4.5 x 1028 moles of sodium fluoride, NaF?

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To begin with, we must translate the number of molecules into moles.

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To calculate the mass of 4.5 x 10^28 moles of sodium fluoride (NaF), you need to multiply the number of moles by the molar mass of NaF.

The molar mass of NaF is the sum of the atomic masses of sodium (Na) and fluorine (F):

Na: 22.99 g/mol F: 18.998 g/mol

Molar mass of NaF = 22.99 g/mol (Na) + 18.998 g/mol (F) = 41.988 g/mol

Now, multiply the molar mass by the number of moles:

Mass = moles × molar mass Mass = 4.5 x 10^28 moles × 41.988 g/mol

Mass ≈ 1.89 x 10^30 grams

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To calculate the number of grams in 4.5 x 10^28 moles of sodium fluoride (NaF), you need to multiply the number of moles by the molar mass of NaF. The molar mass of NaF is the sum of the atomic masses of sodium (Na) and fluorine (F), which are 22.99 grams per mole and 19.00 grams per mole, respectively. So, the molar mass of NaF is 22.99 + 19.00 = 41.99 grams per mole.

Now, to find the mass in grams of 4.5 x 10^28 moles of NaF, you multiply the number of moles by the molar mass:

4.5 x 10^28 moles * 41.99 grams/mole = 1.89455 x 10^30 grams

Therefore, there are 1.89455 x 10^30 grams in 4.5 x 10^28 moles of sodium fluoride.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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