How many grams are in #12.4*10^15# atoms of neon?

Question

Wyatt Atkins · Accepted Answer

Well I know that #6.022xx10^(23)# atoms of neon have a mass of #20.18*g#. How do I know this?

And thus the mass of #12.4xx10^15# #"neon atoms"# #=# #(12.4xx10^15)/(6.022xx10^(23)*mol^-1)xx20.18*g*mol^-1# #=# #??g#

HIX Tutor · Answer

undefined Great question! Let's figure this out step by step.

1. **Know the number of atoms in one mole:** There are about $ 6.022 \times 10^{23} $ atoms in one mole. This is called Avogadro's number.

2. **Find out how many moles we have:** 
   - We have $ 12.4 \times 10^{15} $ atoms.
   - To find moles, we divide the number of atoms by Avogadro's number.
   $$
   \text{Moles of Neon} = \frac{12.4 \times 10^{15}}{6.022 \times 10^{23}}
   $$

3. **Do the math:**
   - Calculate $ 12.4 \div 6.022 $.
   - Multiply the result by $ 10^{15} \div 10^{23} $, which is $ 10^{-8} $.
   - What do you get for the moles?

4. **Find the mass of the moles:**
   - The molar mass of Neon is about $ 20.18 $ grams per mole.
   - Multiply the number of moles you found by $ 20.18 $ grams.

5. **What do you get for the mass?**

Try these steps, and let me know what answers you find!

Henry Antrim · Answer

undefined To find the mass of 12.4 × 10^15 atoms of neon, you need to use the atomic mass of neon and Avogadro's number.

1. Find the molar mass of neon.
2. Convert the number of atoms to moles.
3. Use the molar mass to convert moles to grams.

Molar mass of neon (Ne) ≈ 20.18 g/mol
Avogadro's number (NA) ≈ 6.022 × 10^23 atoms/mol

Mass of 1 mole of neon = 20.18 g
Number of moles = (12.4 × 10^15 atoms) / (6.022 × 10^23 atoms/mol)
Mass = Number of moles × Molar mass

Calculate the mass.

Mateo Aguilar · Answer

undefined To find the mass of 12.4 × 10^15 atoms of neon, you can use the atomic mass of neon, which is approximately 20.18 grams per mole.

1 mole of neon atoms contains 6.022 × 10^23 atoms.

Therefore, you can calculate the mass of 12.4 × 10^15 neon atoms as follows:

Mass = (12.4 × 10^15 atoms / 6.022 × 10^23 atoms/mole) × 20.18 grams/mole

Mass ≈ 0.2039 grams