How many grams are contained in 3.22 moles of dinitrogen tetroxide?

Question

Naomi Aronson · Accepted Answer

Molar mass of #N_2O_3=2xx14+3xx16=76gmol^-1#
Mass of 3.22 moles of #N_2O_3=3.22#moles#xx76g/(mol)=244.72g#

Peyton Adams · Answer

The formula for dinitrogen tetroxide is #N_2O_4#. Assume that:
n - number of moles
m - mass of substance
M - molar mass #n = m -: M# 3.22 moles (n) of #N_2O_4# has been provided for you. Next step is to find out the molar mass (M). Before that, break up the formula, first, to make sure that you know what atoms are present. You can see that Nitrogen and Oxygen are present. If you refer to your periodic table, the molar mass of Nitrogen is 14.0 g/mol and Oxygen 16.0 g/mol. Therefore, the molar mass (M) of dinitrogen tetroxide is:
#[2 xx 14.0 + 4 xx 16.0]# = 92.0 g/mol. Your last step is to find out the mass.
Look back at the #n = m -: M# formula and make m as the subject. Flip it over and it'll become #m = M xx n#. The mass of #N_2O_4# is:
[m = 92.0 g/mol #xx# 3.22 moles] = 296.2 grams.
Note that this answer is rounded to 3 significant figures. Overall, 296.2 grams are contained in 3.22 moles of dinitrogen tetroxide.

Noah Aldrich · Answer

undefined 3.22 moles of dinitrogen tetroxide would contain $3.22 \text{ moles} \times 92.02 \text{ grams/mole} = \textbf{296.12 grams}$, since the molar mass of dinitrogen tetroxide (N2O4) is roughly 92.02 grams per mole.