How many electrons are lost or gained in forming each #Cu^(2+)#?

Answer 1

#Cu rarr Cu^(2+) +2e^-#

Suppose you knew nothing about chemistry, but something about physics and electrical charge. You know that if something is neutral then it has an equal number of positive and negative charges. In the reaction above, we started with a neutral atom (copper metal), and upon (so-called) oxidation we finished with a cupric ion, #Cu^(2+)#. From charge considerations alone (even if we knew nothing about electrons), we must have removed 2 negatively charged particles. Of course, these species are electrons.

Two things are always conserved in chemical reactions: (i) mass and (ii) charge. Is mass always conserved in nuclear reactions?

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Answer 2

Two electrons are lost in forming each Cu^(2+).

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Answer 3

In forming ( \text{Cu}^{2+} ), copper loses two electrons.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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