Home > Organic Chemistry > Brief History of Organic Chemistry

How many double bonds has the following compound: #C_10H_14O_2#?

Answer 1

Well, what is the degree of unsaturation of this molecule?

We got #C_10H_14O_2#....the saturated formula would be #C_10H_22O_2#, #C_nH_(2n+2)O_m#...and thus there are FOUR DEGREES of unsaturation. And each degree of unsaturation corresponds to a double bond OR a ring... And so there COULD be FOUR olefinic bonds in the formula, or four rings, or carbonyl groups, or a mixture... Note that an aryl ring #C_6H_4R_2# corresponds to four degrees of unsaturation...i.e. three formal double bonds constrained in a ring. But we can't go much farther with this question without more data.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Christian Anderson

The compound C10H14O2 has one double bond.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.