# How many atoms are present in a 112 g sample of #CaBr_2#?

Here, the molar mass is 199.886 and the mass is 112g.

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The first step in determining the number of atoms in an 112 g sample of CaBr2 is to calculate the molar mass of the mixture, which is 40.078 g/mol for calcium and 79.904 g/mol for bromine. This gives a total molar mass of 40.078 + (2 * 79.904) = 199.886 g/mol for CaBr2. Next, divide the given mass by the molar mass, which equals 112 g / 199.886 g/mol ≈ 0.560 moles. Since there are two moles of bromine atoms in a mole of CaBr2, multiply the number of moles by Avogadro's number, which is 6.022 x 10^23 atoms/mol, and then multiply by two to account for the two bromine atoms per molecule: 0.560 moles * 6.022 x 10^23 atoms/mol * 2 ≈ 6.77 x 10^23 atoms.

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