How fast will an object with a mass of #8 kg# accelerate if a force of #32 N# is constantly applied to it?

Answer 1

#4"ms"^{-2}#

We must assume that there are no other external forces acting on the object in question. In that case, the net force (which is the sum of all the forces acting on the object) is just #32"N"#.

As per Newton's Second Law,

#F_"Net" = ma#,

where

#F_"Net"# refers to the net force acting on the object,
#m# refers to the mass of the object,
#a# refers to the acceleration of the object.

Upon entering our values into the formula, we obtain

#32"N"=(8"kg")a#.

Consequently,

#a=4"ms"^{-2}#
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Answer 2

To find the acceleration of the object, use Newton's second law, which states that force equals mass times acceleration (F = ma).

Given: Mass (m) = 8 kg Force (F) = 32 N

Using the formula F = ma, rearrange it to solve for acceleration (a): a = F / m

Substitute the given values: a = 32 N / 8 kg

Calculate: a = 4 m/s²

The object will accelerate at a rate of 4 meters per second squared.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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