How fast will an object with a mass of #3 kg# accelerate if a force of #17 N# is constantly applied to it?

Answer 1

#a = 5.67# #ms^-2#

To answer this question just apply the formula: #F = ma#
#F = 17# #N#
#m = 3# #kg#
#17 = 3 xx a#
#17/3 = a#
#a = 5.67# #ms^-2#
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Answer 2

To calculate acceleration, you can use Newton's second law of motion, which states that acceleration is equal to the net force acting on an object divided by its mass. The formula is:

[ \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}} ]

Given that the mass of the object is ( 3 , \text{kg} ) and the force applied is ( 17 , \text{N} ), you can plug these values into the formula to find the acceleration:

[ \text{Acceleration} = \frac{17 , \text{N}}{3 , \text{kg}} ]

[ \text{Acceleration} = 5.67 , \text{m/s}^2 ]

So, the object will accelerate at ( 5.67 , \text{m/s}^2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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