How fast will an object with a mass of #15 kg# accelerate if a force of #42 N# is constantly applied to it?

Answer 1

#2.8# #m#/#s^2#

Since #F=ma#,
where: #F = #force, in terms of Newton (N) #m = #mass, in terms of Kilograms (Kg) #a = #acceleration, in terms of meters per second squared #(m#/#s^2)#
the given is: #m = 15kg# #F = 42N# #a = ?#
using algebraic technique to find the value of #a#,
#F = ma#
#a = F/m#

addressing the issue:

#a = (42N)/(15kg)#
#a = 2.8 # #m#/#s^2#
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Answer 2

To find the acceleration of the object, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula to calculate acceleration (a) is:

a = F / m

Where:

  • a is the acceleration,
  • F is the force applied,
  • m is the mass of the object.

Given that the force (F) is 42 N and the mass (m) is 15 kg:

a = 42 N / 15 kg a ≈ 2.8 m/s²

Therefore, the object will accelerate at approximately 2.8 meters per second squared.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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