How fast will an object with a mass of #15 kg# accelerate if a force of #40 N# is constantly applied to it?

Question

How fast will an object with a mass of #15   kg# accelerate if a force of #40  N# is constantly applied to it?

Benjamin Asiedu · Accepted Answer

The acceleration of the object is #2.67 m/s^2# [forward].

We must make an assumption before we can answer this question. The force of friction, #F_"F"#, will be ignored. The motion generated will be referred to as motion in a positive direction. No direction is given, but a force is applied to the object. The formula we are using is: #F_"NET" = ma# => where #F_"NET"# is the net force in #N#, #m# is the mass in #kg#, and #a# is the acceleration in #m/s^2#. If we ignore friction, the only force is the applied force, #F_"A"#. Thus #F_"NET" = F_"A"#. We can rearrange the equation #F_"NET" = ma#, to get #a# => #a=F_"NET"/m# #a=F_"NET"/m# #=40/15# #=2.67# Therefore, the acceleration of the object is #2.67 m/s^2# [forward]. I hope this is helpful.

Elena Albarran · Answer

undefined To calculate the acceleration of the object, you can use Newton's second law, which states that force equals mass multiplied by acceleration (F = ma). Rearranging the formula to solve for acceleration (a), we get a = F / m.

Substituting the given values:

a = 40 N / 15 kg
a ≈ 2.67 m/s²

The object will accelerate at approximately 2.67 meters per second squared when a force of 40 Newtons is constantly applied to it.

Benjamin Asiedu · Answer

undefined To find the acceleration of the object, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

The formula to calculate acceleration (a) is:

a = F / m

Where:
a = acceleration
F = force applied
m = mass of the object

Given:
F = 40 N
m = 15 kg

Substituting the given values into the formula:

a = 40 N / 15 kg

a ≈ 2.67 m/s²

Therefore, the object will accelerate at approximately 2.67 meters per second squared when a force of 40 Newtons is constantly applied to it.