How does partial pressure affect delta G?

Answer 1

#DeltaG=DeltaG^@+RTln(((P_(NH_3))^2)/(P_(N_2)*(P_(H_2))^3))#

The relationship between #DeltaG# and pressure is: #DeltaG=DeltaG^@+RTlnQ#

Where #Q# is the reaction quotient, that in case of a reaction involving gaseous reactants and products, pressure could be used.

For example: #N_2(g) + 3H_2(g) -> 2NH_3(g)#

The reaction quotient is: #Q=((P_(NH_3))^2)/(P_(N_2)*(P_(H_2))^3)#

Therefore, #DeltaG=DeltaG^@+RTln(((P_(NH_3))^2)/(P_(N_2)*(P_(H_2))^3))#

I recommend this video that explains this concept in details:

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Answer 2

Olivia Anton

Partial pressure affects delta G according to the equation: ΔG = ΔG° + RT * ln(Q), where Q is the reaction quotient. The reaction quotient, Q, is the ratio of the partial pressures of products to reactants, each raised to the power of their stoichiometric coefficients. Changes in partial pressures of reactants and products will alter the value of Q, thus affecting the value of ΔG.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.