How does an ionic bond form?

Answer 1

It's a matter of one atom donating an electron (or more) to another.

Let's take sodium #Na# that has one electron in its outer shell. Losing it, would mean that it would have the 'sacred' inert-gas configuration (full outer shell, just like Neon). Now we have fluorine #F#. It has 7 electrons in its outer shell. If it could have just one more, it would also reach the Neon-status.
They clinch the deal, but now #Na# has become #Na^+# (it's positively charged, because there is one electron short for compensating the charge of the nucleus). And #F# becomes #F^-# for having one too many. These charged atoms are called ions .
And since opposites attract, #Na^+# and #F^-# tend to stick together, in what we call an ionic bond. And a salt (sodium fluride) has formed.
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Answer 2

An ionic bond forms when one atom transfers one or more electrons to another atom, resulting in the formation of positively and negatively charged ions. These ions are then attracted to each other due to their opposite charges, forming an ionic bond.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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