How does a terminal alkyne react in a Grignard reaction, will the carbonyl carbon attack the terminal carbon?

Answer 1

Not in a nucleophilic attack, no.

Actually, the pKa of acetylene for example, is #25#, but the pKa of a Grignard reagent is generally much higher than #50~60# (because it's pretty much the conjugate base of an alkane!).

Remember, a Grignard reagent is basically one of the strongest nucleophiles out there, but it is also one of the strongest bases out there. It's essentially an anionic alkane.

It's much more likely that it will steal a terminal proton from the alkyne like so:

And that deactivates the Grignard reagent. Whoops! The acetylide can still be a pretty nice nucleophile, but not quite as great. The #25~35# orders of magnitude in the pKa is quite a large difference!

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Answer 2

In a Grignard reaction, a terminal alkyne reacts by forming a new carbon-carbon bond with the carbon of the Grignard reagent. The carbonyl carbon does not attack the terminal carbon. Instead, the nucleophilic carbon of the Grignard reagent attacks the electrophilic carbon of the alkyne, leading to the formation of a new carbon-carbon bond and the synthesis of a new compound.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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