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How do you write # y = –(x + 7)^2 – 8# in standard form?

Answer 1

Nathan Axel

#y=-x^2-14x-58#

#"expand " (x+7)^2" using FOIL"#

#rArry=-(x^2+14x+49)-8#

#color(white)(rArry)=-x^2-14x-49-8#

#color(white)(rArry)=-x^2-14x-58larrcolor(red)" in standard form"#

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Answer 2

Hazel Anglin

To write the equation y = –(x + 7)^2 – 8 in standard form, you expand and simplify the expression:

y = –(x + 7)^2 – 8 y = –(x^2 + 14x + 49) – 8 y = –x^2 – 14x – 49 – 8 y = –x^2 – 14x – 57

So, the equation in standard form is: y = -x^2 - 14x - 57.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.