How do you write #y=x^2-8x+20# into vertex form?
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To write ( y = x^2 - 8x + 20 ) into vertex form, complete the square. Then, write it as ( y = a(x - h)^2 + k ), where ( (h, k) ) is the vertex.
Step 1: Rewrite the equation: [ y = (x^2 - 8x) + 20 ]
Step 2: Complete the square for the quadratic term ( x^2 - 8x ): [ y = (x^2 - 8x + 16) - 16 + 20 ]
Step 3: Rewrite the perfect square trinomial and simplify: [ y = (x - 4)^2 + 4 ]
So, the vertex form of ( y = x^2 - 8x + 20 ) is ( y = (x - 4)^2 + 4 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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