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How do you write #y = x^2 + 2x + 5# into vertex form?

Answer 1

Avery Alexander

Vertex form: #y=m(x-a)^2+b# with the vertex at #(a,b)#

#y=x^2+2x+1 +4#

#y=(x+1)^2+4#

#y=(x-(-1))^2+4#

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Answer 2

Jameson Allen

To write ( y = x^2 + 2x + 5 ) into vertex form, complete the square. The vertex form is ( y = a(x - h)^2 + k ), where ( (h, k) ) is the vertex.

Completing the square, we get ( y = (x^2 + 2x + 1) + 4 = (x + 1)^2 + 4 ).

So, the vertex form of the given equation is ( y = (x + 1)^2 + 4 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.