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How do you write #y + 9 = -3(x - 2) # in standard form?

Answer 1

Abigail Allen

#3x+y=-3#

#"the equation of a line in "color(blue)"standard form "# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"rearrange "y+9=-3(x-2)" into this form"#

#rArry+9=-3x+6#

#"add 3x to both sides"#

#3x+y+9=cancel(-3x)cancel(+3x)+6#

#rArr3x+y+9=6#

#"subtract 9 from both sides"#

#3x+ycancel(+9)cancel(-9)=6-9#

#rArr3x+y=-3larrcolor(red)"in standard form"#

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Answer 2

Julia Adams

To write the equation ( y + 9 = -3(x - 2) ) in standard form, expand the right side, distribute -3 across ( x - 2 ), and then rearrange terms to get ( 3x + y = 15 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.