How do you write #y+5=-6(x+7)# in slope intercept form?

Answer 1

#y=-6x-47#

Slope intercept is written in the form of:

#y=mx+c#
#m# is the gradient of the line. #c# is the y-intercept.

You can convert the given equation to the slope intercept form by simplifying the equation and grouping the like terms. Steps are as follow:

#y+5=-6(x+7)#
#y+5=-6x-42#
#y=-6x-47#
and there you have it. The equation has now been converted to slope incercept form (#y=mx+c#).
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Answer 2

To write the equation (y + 5 = -6(x + 7)) in slope-intercept form, which is (y = mx + b) where (m) is the slope and (b) is the y-intercept, follow these steps:

  1. Distribute the -6 to both (x) and 7: (y + 5 = -6x - 42).
  2. Subtract 5 from both sides to get (y) by itself: (y = -6x - 42 - 5).
  3. Combine like terms: (y = -6x - 47).

So, the equation in slope-intercept form is (y = -6x - 47).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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