How do you write #y = 4(x-3)^2+1 # in standard form?
#y=4x^2-24x+37#
Given -
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To write the equation ( y = 4(x-3)^2 + 1 ) in standard form, expand the squared term and simplify:
[ y = 4(x-3)^2 + 1 \ y = 4(x^2 - 6x + 9) + 1 \ y = 4x^2 - 24x + 36 + 1 \ y = 4x^2 - 24x + 37 ]
Thus, the equation in standard form is ( y = 4x^2 - 24x + 37 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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