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How do you write #y = -2(x+4)(x+1)# in standard form?

Answer 1

Ethan Adkins

Using FOIL, we get #y = -2x^2 - 10 - 8.#

# y = -2(x+4)(x+1) #

Using FOIL:

# y = -2 (x^2 + x + 4x + 4) #

# y = -2 x^2 - 10 x - 8 #

That's standard form so we stop.

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Answer 2

Genesis Allen

To write ( y = -2(x+4)(x+1) ) in standard form, you first expand the expression using the distributive property:

[ y = -2(x^2 + 5x + 4) ] [ y = -2x^2 - 10x - 8 ]

Next, rearrange the terms in descending order of degree:

[ y = -2x^2 - 10x - 8 ]

Therefore, the standard form of the quadratic equation is ( y = -2x^2 - 10x - 8 ).

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Answer 3

Jace Anderson

To write the equation ( y = -2(x+4)(x+1) ) in standard form, we need to expand the expression using the distributive property and then arrange it in the form ( ax^2 + bx + c ).

First, let's expand the expression:

( y = -2(x+4)(x+1) )

( = -2(x^2 + x + 4x + 4) )

( = -2(x^2 + 5x + 4) )

Now, let's distribute the -2:

( = -2x^2 - 10x - 8 )

So, the equation ( y = -2(x+4)(x+1) ) in standard form is ( y = -2x^2 - 10x - 8 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.