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How do you write #y = −2 (x +3)^2 – 5# in standard form?

Answer 1

Eva Adamson

Develop y.

y in standard form:

y = -2(x^2 + 6x + 9) - 5 = -2x^2 - 12x - 23

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Answer 2

Genesis Allen

To write ( y = -2(x + 3)^2 - 5 ) in standard form, expand the squared term and simplify:

[ y = -2(x^2 + 6x + 9) - 5 ] [ y = -2x^2 - 12x - 18 - 5 ] [ y = -2x^2 - 12x - 23 ]

Therefore, the equation in standard form is ( y = -2x^2 - 12x - 23 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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