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How do you write #y-11=3(x+4)# in slope intercept form?

Answer 1

Isaiah Anthony

#y = color(red)(3)x + color(blue)(23)#

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

We can transform this equation to slope-intercept form by solving for #y#:

#y - 11 = 3(x + 4)#

#y - 11 = (3 xx x) + (3 xx 4)#

#y - 11 = 3x + 12#

#y - 11 + color(red)(11) = 3x + 12 + color(red)(11)#

#y - 0 = 3x + 23#

#y = 3x + 23#

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Answer 2

Savannah Anderson

To write the equation (y - 11 = 3(x + 4)) in slope-intercept form, distribute 3 into (x + 4) to get (y - 11 = 3x + 12). Then, isolate (y) by adding 11 to both sides, resulting in (y = 3x + 23). So, the equation in slope-intercept form is (y = 3x + 23).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.