How do you write #(x-5)(x+2)# in standard form?

Answer 1

# x^2 - 3x - 10 #

Each term in the 2nd bracket must be multiplied by each term in the 1st. This can be done as follows.

# color(blue)"(x -5 )"(x + 2)#
= #color(blue)"x" (x + 2 )color(blue)"-5"(x + 2 ) = x^2 + 2x - 5x - 10 #

now collect like terms

# rArr (x - 5 )(x + 2 ) = x^2 - 3x - 10 " is in standard form "#
Writing an answer in standard form means , start with the term that has the highest power of the variable, #" in this case " x^2 #followed by terms with decreasing powers until the last term, usually a constant.
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Answer 2

To write the expression (x-5)(x+2) in standard form, you need to multiply the two binomials together and then combine like terms:

(x - 5)(x + 2) = x^2 + 2x - 5x - 10

Simplify by combining like terms:

x^2 - 3x - 10

So, (x-5)(x+2) in standard form is x^2 - 3x - 10.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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