How do you write #(x-5)(x+2)# in standard form?
Each term in the 2nd bracket must be multiplied by each term in the 1st. This can be done as follows.
now collect like terms
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To write the expression (x-5)(x+2) in standard form, you need to multiply the two binomials together and then combine like terms:
(x - 5)(x + 2) = x^2 + 2x - 5x - 10
Simplify by combining like terms:
x^2 - 3x - 10
So, (x-5)(x+2) in standard form is x^2 - 3x - 10.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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