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How do you write the Vertex form equation of the parabola #y = x^2-6x+8#?

Answer 1

#y = (x - 3)^2 - 1#

#y = x^2 - 6x + 8# x-coordinate of vertex: #x = -b/(2a) = 6/2 = 3# y-coordinate of vertex: y(3) = 9 - 18 + 8 = -1 Vertex (3, -1) Vertex form: #y = (x - 3)^2 - 1#

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Answer 2

Isaiah Anthony

To write the vertex form equation of the parabola (y = x^2 - 6x + 8), complete the square:

(y = x^2 - 6x + 8)
(= (x^2 - 6x + 9) - 9 + 8)
(= (x - 3)^2 - 1)

So, the vertex form equation of the parabola is (y = (x - 3)^2 - 1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.