# How do you write the subtraction problem #7/8-9/10# as an addition problem?

To subtract is the same as adding on an inverse.

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To write the subtraction problem ( \frac{7}{8} - \frac{9}{10} ) as an addition problem, you can first find a common denominator for the fractions. The least common multiple (LCM) of 8 and 10 is 40. Then, rewrite each fraction with the common denominator and change the subtraction operation to addition by adding the opposite.

[ \frac{7}{8} - \frac{9}{10} = \frac{7 \times 5}{8 \times 5} - \frac{9 \times 4}{10 \times 4} ]

[ = \frac{35}{40} + \frac{-36}{40} ]

Now, you can add these fractions together:

[ \frac{35}{40} + \frac{-36}{40} = \frac{35 - 36}{40} ]

[ = \frac{-1}{40} ]

Therefore, ( \frac{7}{8} - \frac{9}{10} ) can be written as ( \frac{-1}{40} ) as an addition problem.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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