How do you write the standard form of a line given slope= -5, passes through (-3, -8)?
substitute these values into the equation.
distribute bracket and collect 'like terms'
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To write the standard form of a line given the slope (-5) and passing through the point (-3, -8), you use the point-slope form of a linear equation:
y - y₁ = m(x - x₁)
Substitute the given values:
y - (-8) = -5(x - (-3))
Simplify:
y + 8 = -5(x + 3)
Now, distribute -5:
y + 8 = -5x - 15
Rearrange the equation into standard form:
5x + y = -15 - 8
5x + y = -23
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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