# How do you write the slope of the line tangent to #g(x)=x^2-4# at the point (1,-3)?

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To find the slope of the line tangent to the function g(x) = x^2 - 4 at the point (1, -3), we can use the derivative of the function. The derivative of g(x) is given by g'(x) = 2x.

To find the slope at the point (1, -3), we substitute x = 1 into the derivative equation: g'(1) = 2(1) = 2.

Therefore, the slope of the line tangent to g(x) = x^2 - 4 at the point (1, -3) is 2.

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