How do you write the slope of the line tangent to #f(x)=3-2x# at the point (-1,5)?

Answer 1

The slope of the line tangent to #f(x)=3-2x# is #-2#.

As #f(x)=3-2x# or #y=3-2x# is a linear function, it is the equation of a straight line, whose slope is #-2#.

A straight line is itself a tangent, at any of its point and as such

the slope of the line tangent to #f(x)=3-2x# is #-2#.
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Answer 2

To find the slope of the line tangent to the function f(x) = 3 - 2x at the point (-1,5), we can use the derivative of the function. The derivative of f(x) is -2. Therefore, the slope of the tangent line is -2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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