How do you write the slope intercept form of the line #3x-2y=-16#?

Answer 1

#y = 3/2x + 8#

Simply make y the subject of the equation:

#-2y = -16 - 3x#
#y = 8 + 3/2x#
#y = 3/2x + 8#
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Answer 2

#y=3/2x+8#

Slope intercept form is defined as #y=mx+b# where #m# is the slope an #b# is the #y#-intercept.
In this case we have #3x-2y=-16#. To write this in slope intercept form we must solve for #y#. Thus,
Subtract #3x# to both sides:
#cancel(3x-3x)-2y=-3x-16#
#-2y=-3x-16#
Divide #-2# to both sides:
#cancel(-2/-2)y=(-3x-16)/-2#

Simplify:

#y=3/2x+8#
This is now written in slope intercept form where #m# (the slope) is #3/2# and our #y#-intercept is #8#
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Answer 3

To write the slope-intercept form of the line 3x - 2y = -16, you would first isolate y by subtracting 3x from both sides to get -2y = -3x - 16. Then, divide both sides by -2 to solve for y. The slope-intercept form is y = (3/2)x + 8.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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