How do you write the quadratic in vertex form given #y=-2x^2+6x+1#?
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To write a quadratic equation in vertex form, you can use the formula y = a(x - h)^2 + k, where (h, k) represents the coordinates of the vertex. First, factor out the coefficient of x^2 from the given equation: y = -2(x^2 - 3x) + 1. Complete the square inside the parentheses: y = -2(x^2 - 3x + 9/4 - 9/4) + 1. Rewrite the equation: y = -2(x^2 - 3x + 9/4) + 9/2 + 1. Factor and simplify: y = -2(x - 3/2)^2 + 11/2. The quadratic equation in vertex form is y = -2(x - 3/2)^2 + 11/2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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