How do you write the quadratic in vertex form given #f(x) = 3x^2 + 6x 2#?
To enter this into the Vertex Form, we can utilize the Completing the Square procedure.
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To write the quadratic function ( f(x) = 3x^2 + 6x  2 ) in vertex form, follow these steps:

Complete the square for the quadratic term: [ f(x) = 3(x^2  2x)  2 ]

To complete the square inside the parentheses, halve the coefficient of the linear term (6x) and square it: [ (3(x^2  2x + 1  1))  2 ]

Rewrite the expression inside the parentheses: [ 3((x  1)^2  1)  2 ]

Distribute the 3: [ 3(x  1)^2 + 3  2 ]

Combine like terms: [ 3(x  1)^2 + 1 ]
So, the quadratic function ( f(x) = 3x^2 + 6x  2 ) in vertex form is: [ f(x) = 3(x  1)^2 + 1 ]
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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