How do you write the quadratic function #y=x^2+14x+11# in vertex form?
The quadratic function in vertex form is
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To write the quadratic function (y = x^2 + 14x + 11) in vertex form, follow these steps:

Complete the square for the quadratic term: (y = (x^2 + 14x) + 11) (y = (x^2 + 14x + 49)  49 + 11) (y = (x + 7)^2  38)

Rewrite the equation in vertex form: (y = (x + h)^2 + k) where (h = 7) and (k = 38)
Therefore, the quadratic function (y = x^2 + 14x + 11) in vertex form is (y = (x + 7)^2  38).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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