How do you write the point slope form of the equation given m=2/3 and (3,2)?

Answer 1

#y-2=2/3(x-3)#

The equation of a line in #color(blue)"point-slope form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|))# where m represents the slope and # (x_1,y_1)" a point on the line"#

#"here " m=2/3" and " (x_1,y_1)=(3,2)#

#"substitute these values into the equation"#

#rArry-2=2/3(x-3)larrcolor(red)" in point-slope form"#

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Answer 2

Abigail Allen

To write the point-slope form of the equation given ( m = \frac{2}{3} ) and the point ((3,2)), you use the formula ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) are the coordinates of the given point and ( m ) is the slope. Substituting ( m = \frac{2}{3} ) and ( (x_1, y_1) = (3,2) ) into the formula, the point-slope form of the equation is ( y - 2 = \frac{2}{3}(x - 3) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.