How do you write the point slope form of the equation given (5,5) and slope 3/5?
We already have these two quantities:
Let's substitute this information into the point slope formula:
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To write the point-slope form of the equation with the given point (5,5) and slope 3/5, use the formula: y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the slope. Substituting the given values, the equation becomes: y - 5 = (3/5)(x - 5).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you write an equation for a line with m=3.5 and #f(-2)=1#?
- What is the equation of the line between #(-3,3)# and #(-4,1)#?
- What is the slope of any line perpendicular to the line passing through #(-3,1)# and #(7,2)#?
- What is the equation of the line between #(3,16)# and #(2,27)#?
- How do you write an equation of a line perpendicular to #y=-1/2x+2/3# and passes through (2,3)?

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