Home > Algebra > Linear Equations in Point-Slope Form

How do you write the point slope form of the equation given (4,-5) and m=6?

Answer 1

Eli Assouline

#y=6x-29#
graph{y=6x-29 [-10, 10, -5, 5]}

The formula to find the equation is #y=mx+b#

Since we know that #m=6#, the equation we have so far would be #y=6x+b#.

Now, we will find #b#.

Plug in #(4, -5)# where #x=4# and #y=-5#

#-5=6*4+b#

Switch sides: #6*4+b=-5#

Multiply the numbers: #24+b=-5#

Subtract #24# from both sides: #24+bcolor(red)-color(red)24=-5color(red)-color(red)24#

Simplify: #b=-29#

Therefore, the whole equation is: #y=6x-29#.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Eva Abramson

#y+5=6(x-4)#

Remember that the point-slope form equation looks like this:

#y-k=m(x-h)#

Where #h# and #k# represents a point on the line and #m# is the slope.

The point should have the coordinates like this: #(h,k)#

What we have to do is substitute the values in like so:

#y-k=m(x-h)# #y-(-5)=6(x-4)# So the answer must be: #y+5=6(x-4)#

Sweeeeet

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 3

Savannah Anderson

The point-slope form of a linear equation is: y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope.

Substituting the given values: y - (-5) = 6(x - 4)

Expanding: y + 5 = 6x - 24

Rearranging to standard form: 6x - y = 29

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.