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How do you write the point slope form of the equation given (4,-5) and (0,-1)?

Answer 1

The equation of the line is #y = -x-1#

The slope = #(y_2-y_1)/(x_2-x_1)= (-1-(-5))/(0-4)=-4/4=-1 # Let the equation of the line is #y=mx+c or y= -1*x+c# The point #(4,-5)# is on the line , so it will satisfy the equation. #y= -x=c or -5= -4+c :. c =-5+4=-1# Hence the equation of the line is #y = -x-1# graph{-x-1 [-10, 10, -5, 5]} [Ans]

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Answer 2

Kennedy Adams

To write the point-slope form of the equation using the points (4, -5) and (0, -1):

Calculate the slope using the formula: (m = \frac{{y_2 - y_1}}{{x_2 - x_1}}).
Substitute the coordinates into the formula: (m = \frac{{-1 - (-5)}}{{0 - 4}}).
Simplify to find the slope.
Choose one of the points, for example (4, -5), and use the point-slope formula: (y - y_1 = m(x - x_1)).
Substitute the slope and the coordinates of the chosen point into the formula to find the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.