How do you write the point slope form of the equation given (4,2) and (1,-1)?

Answer 1

#y-2=(x-4)#

The equation of a line in #color(blue)"point-slope form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))# where m represents the slope and # (x_1,y_1)" a point on the line"#
To calculate m, use the #color(blue)"gradient formula"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))# where # (x_1,y_1),(x_2,y_2)" are 2 coordinate points"#

The 2 points here are (4 ,2) and (1 ,-1)

let # (x_1,y_1)=(4,2)" and " (x_,y_2)=(1,-1)#
#rArrm=(-1-2)/(1-4)=(-3)/(-3)=1#
Use either of the 2 given points for # (x_1,y_1)#
#"Using " (4,2)=(x_1,y_1)" and " m=1#
#y-2=1(x-4)larrcolor(red)" in point slope form"#
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Answer 2

To write the point-slope form of the equation given two points (4,2) and (1,-1), you first calculate the slope using the formula:

slope = (change in y) / (change in x)

Then, choose one of the points and plug its coordinates and the slope into the point-slope formula:

y - y₁ = m(x - x₁)

where (x₁, y₁) is one of the points, and m is the slope you calculated.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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