How do you write the point slope form of an equation for the horizontal line that passes through (4,-2)?

Answer 1
If the line is horizontal then the slope is #0# in slope-point form, that is #(y-y_1) = m(x-x_1)# this would be #y+2 = 0(x-4)# and that's the "correct" answer to the question but why would anyone leave it in that form? #y+2=0# or #y=-2#
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Answer 2

The point-slope form of the equation for a horizontal line passing through the point (4, -2) is y = -2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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