How do you write the point slope form of an equation for a lint that passes through (9,-5) with m=0?

Question

Eva Adamson · Accepted Answer

See a solution process below:

The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))# Where #color(blue)(m)# is the slope and #(color(red)(x_1, y_1))# is a point the line passes through. Substituting the slope and values from the point in the problem gives: #(y - color(red)(-5)) = color(blue)(0)(x - color(red)(9))# #(y + color(red)(5)) = color(blue)(0)(x - color(red)(9))#

Genesis Allen · Answer

undefined The point-slope form of an equation for a line is $ y - y_1 = m(x - x_1) $, where $ (x_1, y_1) $ is a point on the line and $ m $ is the slope of the line. Since the slope is 0, the equation simplifies to $ y - (-5) = 0(x - 9) $, which further simplifies to $ y + 5 = 0 $.

Ethan Adkins · Answer

undefined The point-slope form of the equation of a line is given by:

y - y1 = m(x - x1)

Where (x1, y1) are the coordinates of a point on the line, and m is the slope of the line.

Given that the line passes through the point (9, -5) and has a slope m = 0, substituting these values into the point-slope form:

y - (-5) = 0(x - 9)

Which simplifies to:

y + 5 = 0

Therefore, the equation of the line in point-slope form is:

y + 5 = 0