# How do you write the point slope form of an equation for a lint that passes through (9,-5) with m=0?

See a solution process below:

Substituting the slope and values from the point in the problem gives:

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The point-slope form of an equation for a line is ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is a point on the line and ( m ) is the slope of the line. Since the slope is 0, the equation simplifies to ( y - (-5) = 0(x - 9) ), which further simplifies to ( y + 5 = 0 ).

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The point-slope form of the equation of a line is given by:

y - y1 = m(x - x1)

Where (x1, y1) are the coordinates of a point on the line, and m is the slope of the line.

Given that the line passes through the point (9, -5) and has a slope m = 0, substituting these values into the point-slope form:

y - (-5) = 0(x - 9)

Which simplifies to:

y + 5 = 0

Therefore, the equation of the line in point-slope form is:

y + 5 = 0

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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