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How do you write the point slope form of an equation for a lint that passes through (9,1) with m=2/3?

Answer 1

Eva Adamson

#(y - color(red)(1)) = color(blue)(2/3)(x - color(red)(9))#

The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the slope and point from the problem gives:

#(y - color(red)(1)) = color(blue)(2/3)(x - color(red)(9))#

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Answer 2

Eva Adamson

To write the point-slope form of an equation for a line that passes through (9,1) with a slope of 2/3, you use the formula ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) are the coordinates of the given point. Substitute the values into the formula to get ( y - 1 = \frac{2}{3}(x - 9) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.