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How do you write the function in standard form #y=(5x+8)(4x+1)#?

Answer 1

See the entire solution process below.

To write this equation in standard form you must multiply the two terms on the right side of the equation. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#y = (color(red)(5x) + color(red)(8))(color(blue)(4x) + color(blue)(1))# becomes:

#y = (color(red)(5x) xx color(blue)(4x)) + (color(red)(5x) xx color(blue)(1)) + (color(red)(8) xx color(blue)(4x)) + (color(red)(8) xx color(blue)(1))#

#y = 20x^2 + 5x + 32x + 8#

We can now combine like terms:

#y = 20x^2 + (5 + 32)x + 8#

#y = 20x^2 + 37x + 8#

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Answer 2

Jace Anderson

To write the function in standard form, distribute and simplify the expression:

y = (5x + 8)(4x + 1) = 5x(4x) + 5x(1) + 8(4x) + 8(1) = 20x^2 + 5x + 32x + 8 = 20x^2 + 37x + 8

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.