# How do you write the first five terms of the sequence #3n^2+4# using the nth term rule?

7 , 16 , 31 , 52 , 79

To generate the terms in the sequence , substitute in appropriate values for n and evaluate.

In this case, n = 1,2,3,4,5.

You can handle the last two on your own, I'm sure.

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To write the first five terms of the sequence (3n^2 + 4) using the nth term rule, you substitute values of (n) from 1 to 5 into the expression (3n^2 + 4) and calculate the corresponding terms.

- When (n = 1), (3(1)^2 + 4 = 3(1) + 4 = 3 + 4 = 7).
- When (n = 2), (3(2)^2 + 4 = 3(4) + 4 = 12 + 4 = 16).
- When (n = 3), (3(3)^2 + 4 = 3(9) + 4 = 27 + 4 = 31).
- When (n = 4), (3(4)^2 + 4 = 3(16) + 4 = 48 + 4 = 52).
- When (n = 5), (3(5)^2 + 4 = 3(25) + 4 = 75 + 4 = 79).

Therefore, the first five terms of the sequence are 7, 16, 31, 52, and 79.

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