How do you write the equation of the parabola in vertex form given the vertex (-2, -8) and passes through the point (7, -494)?
# y =- 6(x+2)^2 - 8 #
In vertex form, a parabola's equation is
Here, the vertex's coordinates are provided, so
In addition, since the parabola passes through point (7, -494), enter x = 7 and y = -494 into the equation to find the value of a.
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The equation of a parabola in vertex form is ( y = a(x - h)^2 + k ), where (h, k) is the vertex. Substituting the given vertex (-2, -8), we have ( y = a(x + 2)^2 - 8 ). To find 'a', substitute the point (7, -494) into the equation and solve for 'a'. ( -494 = a(7 + 2)^2 - 8 ) leads to ( a = -2 ). Thus, the equation of the parabola is ( y = -2(x + 2)^2 - 8 ).
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The equation of a parabola in vertex form is ( y = a(x - h)^2 + k ), where ( (h, k) ) is the vertex. Substituting the given vertex ( (-2, -8) ), we have ( y = a(x + 2)^2 - 8 ). To find ( a ), substitute the point ( (7, -494) ) into the equation and solve for ( a ).
[ -494 = a(7 + 2)^2 - 8 ]
[ -494 = a(9)^2 - 8 ]
[ -494 = 81a - 8 ]
[ -486 = 81a ]
[ a = -6 ]
Therefore, the equation of the parabola in vertex form is ( y = -6(x + 2)^2 - 8 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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