How do you write the equation of the line parallel to y = 3x - 4 and passing through the point (-2, 5)?
Parallel lines have the same slopes.
The slope of the new line will have the same slope as the given line:
If you have the slope and one point , substitute them into a formula which is based on the formula for slope given above.
Simplify to get the required equation of the line.
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To write the equation of a line parallel to y = 3x - 4 and passing through the point (-2, 5), we use the fact that parallel lines have the same slope. The slope of the line y = 3x - 4 is 3. So, the slope of the parallel line will also be 3. Now, we use the point-slope form of a line, which is y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the slope. Substituting the values, we get y - 5 = 3(x - (-2)). Simplifying, we get y - 5 = 3(x + 2). Expanding and simplifying further, we get y - 5 = 3x + 6. Finally, we add 5 to both sides to isolate y, yielding y = 3x + 11. Therefore, the equation of the line parallel to y = 3x - 4 and passing through the point (-2, 5) is y = 3x + 11.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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