# How do you write the equation of the circle with the given center and radius: Center at (3, -6); radius = 5?

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The equation of a circle with center (h, k) and radius r is given by the formula:

((x - h)^2 + (y - k)^2 = r^2)

Given the center (3, -6) and radius 5, the equation of the circle is:

((x - 3)^2 + (y + 6)^2 = 5^2)

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you find the center and radius of the circle #x^2 + y^2 – 8x – 6y – 75 = 0#?
- What are the equations of the tangents drawn from the point (0,1) to the circle #x^2+y^2-2x+4y=0#?
- How do you find the center and radius of the circle #(3x-1)^2 + (3y+3)^2 = -1#?
- What is the standard form of the equation of a circle with center at (-3, 1) and through the point (2, 13)?
- How do you write the equation of the circle in standard form, identify the center and radius of #x^2+y^2-2x+6y+9=0#?

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