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How do you write the equation of the circle with the given center and radius: Center at (3, -6); radius = 5?

Answer 1

You can use the general telationship:
#(x-h)^2+(y-k)^2=r^2#

In the above relationship #(h,k)# are the coordinates of the center while #r# is the radius of your circle. You should get:

#(x-3)^2+(y+6)^2=5^2#

Try to expand this equation by yourself to get to the equation of the circle in the form: #x^2+y^2+....=0#

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Answer 2

Anna Allen

The equation of a circle with center (h, k) and radius r is given by the formula:

((x - h)^2 + (y - k)^2 = r^2)

Given the center (3, -6) and radius 5, the equation of the circle is:

((x - 3)^2 + (y + 6)^2 = 5^2)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.