How do you write the equation of a line which passes through (0, -3) and has a slope of -5?

Answer 1

Eli Assouline

#y=-5x-3#

When given a set of points and the slope, use the point slope formula, which is:

#y-y_1=m(x-x_1)#

Where #y_1# is the #y# in the set of points #x_1# is the #x# in the set of points And #m# is the slope

Plug in the numbers into the equation

#y+3=-5(x-0)#

Distribute the #-5# throughout the set of parenthesis

#y+3=-5x+0

Subtract #3# on both sides of the equation

#y=-5x-3#

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Answer 2

Savannah Anderson

To write the equation of a line passing through the point (0, -3) with a slope of -5, you can use the point-slope form of a linear equation:

[ y - y_1 = m(x - x_1) ]

where ( (x_1, y_1) ) represents the given point and ( m ) represents the slope.

Substituting the given values into the formula:

[ y - (-3) = -5(x - 0) ]

Simplify:

[ y + 3 = -5x ]

This is the equation of the line passing through (0, -3) with a slope of -5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.