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How do you write the equation of a line that passes through (4,-3) and has a slope of -3/4?

Answer 1

#y = -3/4x#

#y = mx + b#

where: #m =# slope of the line #b = # y-intercept

the slope is already given (#-3/4#). All that remains is to find the y-intercept.

To find the y-intercept, we use the coordinates of a point which we know lies on the line. Such a point was also given #(4, -3)#.

#y = -3/4x + b#

#=> -3 = -3/4(4) + b#

#=> -3 = -3 + b# #=> b = 0#

Since the y-intercept is 0, the equation of the line is

#y = -3/4x#

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Answer 2

Jameson Allen

To write the equation of a line passing through the point (4,-3) with a slope of -3/4, you can use the point-slope form of a linear equation. The equation is: y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the slope. Substituting the given values, the equation becomes: y - (-3) = (-3/4)(x - 4). Simplify to get the final equation: y + 3 = (-3/4)(x - 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.