How do you write the equation of a line that passes through (2,5) and has an intercept of 3?
Eva Abramson(if a slope of 3)
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Isaiah AnthonyYou can write the equation of a line in slope-intercept form ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. To find the slope, use the given point (2,5) and the y-intercept (0,3). Then, substitute the values into the slope formula ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ). Once you have the slope, substitute it and the y-intercept into the equation ( y = mx + b ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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